Returns True
if x
is non-decreasing.
View aliases
Compat aliases for migration
See Migration guide for more details.
tf.compat.v1.debugging.is_non_decreasing
, tf.compat.v1.is_non_decreasing
, tf.compat.v1.math.is_non_decreasing
tf.math.is_non_decreasing(
x, name=None
)
Elements of x
are compared in row-major order. The tensor [x[0],...]
is non-decreasing if for every adjacent pair we have x[i] <= x[i+1]
.
If x
has less than two elements, it is trivially non-decreasing.
See also: is_strictly_increasing
x1 = tf.constant([1.0, 1.0, 3.0])
tf.math.is_non_decreasing(x1)
<tf.Tensor: shape=(), dtype=bool, numpy=True>
x2 = tf.constant([3.0, 1.0, 2.0])
tf.math.is_non_decreasing(x2)
<tf.Tensor: shape=(), dtype=bool, numpy=False>
Returns | |
---|---|
Boolean Tensor , equal to True iff x is non-decreasing.
|