tensorflow::
ops::
SegmentMin
#include <math_ops.h>
Computes the minimum along segments of a tensor.
Summary
Read the section on segmentation for an explanation of segments.
Computes a tensor such that \(output_i = (data_j)\) where
min
is over
j
such that
segment_ids[j] == i
.
If the min is empty for a given segment ID
i
,
output[i] = 0
.
For example:
c = tf.constant([[1,2,3,4], [4, 3, 2, 1], [5,6,7,8]]) tf.segment_min(c, tf.constant([0, 0, 1])) # ==> [[1, 2, 2, 1], # [5, 6, 7, 8]]
Args:
- scope: A Scope object
-
segment_ids: A 1-D tensor whose size is equal to the size of
data
's first dimension. Values should be sorted and can be repeated.
Returns:
-
Output
: Has same shape as data, except for dimension 0 which has sizek
, the number of segments.
Constructors and Destructors |
|
---|---|
SegmentMin
(const ::
tensorflow::Scope
& scope, ::
tensorflow::Input
data, ::
tensorflow::Input
segment_ids)
|
Public attributes |
|
---|---|
operation
|
|
output
|
Public functions |
|
---|---|
node
() const
|
::tensorflow::Node *
|
operator::tensorflow::Input
() const
|
|
operator::tensorflow::Output
() const
|
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Public attributes
Public functions
SegmentMin
SegmentMin( const ::tensorflow::Scope & scope, ::tensorflow::Input data, ::tensorflow::Input segment_ids )
node
::tensorflow::Node * node() const
operator::tensorflow::Input
operator::tensorflow::Input() const
operator::tensorflow::Output
operator::tensorflow::Output() const