TensorFlow 1 version
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View source on GitHub
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Computes the mean of elements across dimensions of a tensor.
tf.math.reduce_mean(
input_tensor, axis=None, keepdims=False, name=None
)
Reduces input_tensor along the dimensions given in axis by computing the
mean of elements across the dimensions in axis.
Unless keepdims is true, the rank of the tensor is reduced by 1 for each
entry in axis. If keepdims is true, the reduced dimensions are retained
with length 1.
If axis is None, all dimensions are reduced, and a tensor with a single
element is returned.
For example:
x = tf.constant([[1., 1.], [2., 2.]])tf.reduce_mean(x)<tf.Tensor: shape=(), dtype=float32, numpy=1.5>tf.reduce_mean(x, 0)<tf.Tensor: shape=(2,), dtype=float32, numpy=array([1.5, 1.5], dtype=float32)>tf.reduce_mean(x, 1)<tf.Tensor: shape=(2,), dtype=float32, numpy=array([1., 2.], dtype=float32)>
Args | |
|---|---|
input_tensor
|
The tensor to reduce. Should have numeric type. |
axis
|
The dimensions to reduce. If None (the default), reduces all
dimensions. Must be in the range [-rank(input_tensor),
rank(input_tensor)).
|
keepdims
|
If true, retains reduced dimensions with length 1. |
name
|
A name for the operation (optional). |
Returns | |
|---|---|
| The reduced tensor. |
Numpy Compatibility
Equivalent to np.mean
Please note that np.mean has a dtype parameter that could be used to
specify the output type. By default this is dtype=float64. On the other
hand, tf.reduce_mean has an aggressive type inference from input_tensor,
for example:
x = tf.constant([1, 0, 1, 0])tf.reduce_mean(x)<tf.Tensor: shape=(), dtype=int32, numpy=0>y = tf.constant([1., 0., 1., 0.])tf.reduce_mean(y)<tf.Tensor: shape=(), dtype=float32, numpy=0.5>