tensorflow:: ops:: SegmentSumV2
#include <math_ops.h>
Computes the sum along segments of a tensor.
Summary
Read the section on segmentation for an explanation of segments.
Computes a tensor such that \(output_i = \sum_j data_j\) where sum is over j
such that segment_ids[j] == i
.
If the sum is empty for a given segment ID i
, output[i] = 0
.
Note that this op is currently only supported with jit_compile=True.
Args:
- scope: A Scope object
- segment_ids: A 1-D tensor whose size is equal to the size of
data
's first dimension. Values should be sorted and can be repeated. The values must be less thannum_segments
.
Caution: The values are always validated to be sorted on CPU, never validated on GPU.
Returns:
Output
: Has same shape as data, except for the firstsegment_ids.rank
dimensions, which are replaced with a single dimension which has sizenum_segments
.
Constructors and Destructors |
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SegmentSumV2(const ::tensorflow::Scope & scope, ::tensorflow::Input data, ::tensorflow::Input segment_ids, ::tensorflow::Input num_segments)
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Public attributes |
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operation
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output
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Public functions |
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node() const
|
::tensorflow::Node *
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operator::tensorflow::Input() const
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operator::tensorflow::Output() const
|
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Public attributes
operation
Operation operation
output
::tensorflow::Output output
Public functions
SegmentSumV2
SegmentSumV2( const ::tensorflow::Scope & scope, ::tensorflow::Input data, ::tensorflow::Input segment_ids, ::tensorflow::Input num_segments )
node
::tensorflow::Node * node() const
operator::tensorflow::Input
operator::tensorflow::Input() const
operator::tensorflow::Output
operator::tensorflow::Output() const