TensorFlow 2 version
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View source on GitHub
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Return the elements, either from x or y, depending on the condition. (deprecated)
tf.where(
condition, x=None, y=None, name=None
)
If both x and y are None, then this operation returns the coordinates of
true elements of condition. The coordinates are returned in a 2-D tensor
where the first dimension (rows) represents the number of true elements, and
the second dimension (columns) represents the coordinates of the true
elements. Keep in mind, the shape of the output tensor can vary depending on
how many true values there are in input. Indices are output in row-major
order.
If both non-None, x and y must have the same shape.
The condition tensor must be a scalar if x and y are scalar.
If x and y are tensors of higher rank, then condition must be either a
vector with size matching the first dimension of x, or must have the same
shape as x.
The condition tensor acts as a mask that chooses, based on the value at each
element, whether the corresponding element / row in the output should be taken
from x (if true) or y (if false).
If condition is a vector and x and y are higher rank matrices, then it
chooses which row (outer dimension) to copy from x and y. If condition
has the same shape as x and y, then it chooses which element to copy from
x and y.
Args | |
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condition
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A Tensor of type bool
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x
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A Tensor which may have the same shape as condition. If condition is
rank 1, x may have higher rank, but its first dimension must match the
size of condition.
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y
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A tensor with the same shape and type as x.
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name
|
A name of the operation (optional) |
Returns | |
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A Tensor with the same type and shape as x, y if they are non-None.
Otherwise, a Tensor with shape (num_true, rank(condition)).
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Raises | |
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ValueError
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When exactly one of x or y is non-None.
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