View source on GitHub |
Normalizes along dimension axis
using an L2 norm. (deprecated arguments)
tf.math.l2_normalize(
x, axis=None, epsilon=1e-12, name=None, dim=None
)
Used in the notebooks
Used in the tutorials |
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For a 1-D tensor with axis = 0
, computes
output = x / sqrt(max(sum(x**2), epsilon))
For x
with more dimensions, independently normalizes each 1-D slice along
dimension axis
.
1-D tensor example:
>>> x = tf.constant([3.0, 4.0])
>>> tf.math.l2_normalize(x).numpy()
array([0.6, 0.8], dtype=float32)
2-D tensor example:
>>> x = tf.constant([[3.0], [4.0]])
>>> tf.math.l2_normalize(x, 0).numpy()
array([[0.6],
[0.8]], dtype=float32)
x = tf.constant([[3.0], [4.0]])
tf.math.l2_normalize(x, 1).numpy()
array([[1.],
[1.]], dtype=float32)
Returns | |
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A Tensor with the same shape as x .
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